Gradient of dot product using suffix notation

spacetimedude
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Homework Statement


Find the gradient of \underline{\nabla}(\underline{a}\cdot\underline{r})^n where a is a constant vector, using suffix notation and chain rule.

Homework Equations


On the previous problem,s I found that grad(a.r)=a and grad(r)=\underline{\hat{r}}

The Attempt at a Solution


<br /> \underline{e_i}(\frac{\partial }{\partial x_i})(\underline{a}\cdot\underline{r})^n=\underline{e_i}(\frac{\partial }{\partial x_i}(a_jx_j)^n)=\underline{e_i}(n(a_jx_j)^{n-1}(a_j\delta_{ij}))<br />
I'm sure that the last step is wrong so could someone lead me to the right direction?
Thank you!
 
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The derivative of (ax)^n is NOT n(ax)^{n-1}.
 
HallsofIvy said:
The derivative of (ax)^n is NOT n(ax)^{n-1}.
That is what I thought. Could you explain that step?
 
Just after I wrote that I noticed that you also had "a_j\delta_{ij}". The derivative of (ax)^n= a^nx^n is na^nx^{n-1} but that can also be written as (ax)^{n-2}(a) where the last "a" is due to the chain rule. Was that what you meant?
 
##na^nx^{n-1}## is confusing. The inner product ##(a_j x_j)^{n-1}## is lost.

When I write it out and then put it back together again ##
\underline{e_i}(n(a_jx_j)^{n-1}(a_j\delta_{ij}))## seems OK.
##
na_i \underline{e_i}\;(a_jx_j)^{n-1}## might be somewhat more elegant,
and even that can be simplified further !
 
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