Gradient of the tangent to the curve question

Thread starter Hannelore
Start date Jan 1, 2008
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Curve Gradient Tangent

AI Thread Summary

To find the gradient of the tangent to the curve y=sin(2x-1) at the point P (1/2, 0), the derivative of the function must be calculated. The derivative represents the slope of the tangent line at a specific point on the curve. Understanding the geometrical interpretation of the derivative at a point is crucial, as it indicates the rate of change of the function at that point. To solve the problem, one must differentiate the function and evaluate it at x=1/2. This will yield the gradient of the tangent at point P.

Jan 1, 2008

Hannelore

Homework Statement

The point P (1/2, 0) lies on the graph of the curve of y=sin(2x-1) Find the gradient of the tangent to the curve of P

Homework Equations

...I don't know

The Attempt at a Solution

I don't know where to start with this problem

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Jan 1, 2008

Rainbow Child

What is the geometrical interpretation of the derivative f'(x_o) at the point (x_o,f(x_o))?

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