Graph, figure and maximum and minimum

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Homework Help Overview

The discussion revolves around the function f(x,y) = x^2*y, defined within a specific region bounded by the inequalities -1 ≤ x ≤ 1 and x ≤ y ≤ x + 2. Participants are examining the minimum and maximum values of the function based on a provided figure.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the correctness of the identified minimum and maximum values based on the figure. There is also a discussion about the number of coordinates needed to specify these extrema, with some clarification on the nature of the function and its variables.

Discussion Status

The conversation is ongoing, with participants exploring different aspects of the problem, including the interpretation of the region and the method for finding extrema. Some guidance has been provided regarding the use of the gradient and the evaluation of boundary points, but no consensus has been reached on the final values.

Contextual Notes

There is a noted confusion regarding the terminology used to describe the region of interest, with a suggestion that "region" is more appropriate than "interval." Additionally, the boundaries and points of interest for evaluating the function are being discussed.

Niles
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Homework Statement


Please take a look at the attached figure.

It is the function f(x,y) = x^2*y in the interval -1 =< x =< 1 and x =< y =< x+2.

From the figure, is it correct that the minimum is in f(-1,-1) = -1 and the maximum is in f(1,3) = 3?
 

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The level curve is plottet as well
 
Do I have to give 2 or 3 coordinates?
 
Since f is a function of 2 variables, you specify the point at which f has a maximum or minimum by giving the x and y values of the point. The third variable shown in the graph is the value of f. In order to determine the maximum and minimum values, you can take the gradient of f inside the region shown and determine if there are any (x,y) points where it is 0. Then look on the boundaries. Since the problem says, " in the interval -1 =< x =< 1 and x =< y =< x+2" (that's not actually an interval, by the way. It should say "region".) The boundaries are x= -1, with y between -1 and 1 (replace x in the formula by -1 to get a function of y only), y= x with x between -1 and 1 (replace y in the formula by x to get a function of x only), y= x+2 with x between -1 and 1 (replace y in the formula by x+ 2 to get a function of x only), and x= 1 with y between 1 and 3 (replace x in the formula by 1 to get a function of x only). Again, take the derivative to find if there are any places where it is 0. Finally, the boundaries of those- the corners of the region, (-1, -1), (-1, 1), (1, 1), and (1, 3). Check the value of f at all of those points to see which gives the maximum value and which gives the minimum value.
 

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