Graphing a Circle: Find Center, Radius & Intercepts

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The equation x^2 + y^2 – x + 2y + 1 = 0 can be rewritten in standard form by completing the square, resulting in (x - 1/2)^2 + (y + 1)^2 = 1/4. The center of the circle is located at (1/2, -1) and the radius is 1/2. The discussion confirms the correct method for finding the center and radius, emphasizing the importance of completing the square. Additionally, the intercepts can be determined from the standard form of the equation. This approach effectively clarifies the process of graphing the circle.
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Consider x^2 + y^2 – x + 2y + 1 = 0.
(a) Find the coordinates of the center and the length of the radius.
(b) Determine the coordinates of the intercepts.
(c) Graph the circle.



I'm really lost on this one. I tried plugging in numbers but I seriously doubt that's how I'm supposed to do it. Can someone point me in the right direction? Thanks
 
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Standard Form versus General Form.
Completing the Square.
 
oh so just (x-1/2)^2 + (y+1)^2 = 1/4? center would be at (1/2, -1) and radius is sqrt(1/4)=(1/2)?
 
elitespart said:
oh so just (x-1/2)^2 + (y+1)^2 = 1/4? center would be at (1/2, -1) and radius is sqrt(1/4)=(1/2)?

Yup! :biggrin:
 
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