Graphing Polynomial Functions: Finding x-Intercepts

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Buddah
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Graph each function given below on a graphing calculator to find a general rule for determining when a graph crosses the x-axis at an x intercept or when the graph just touches and turns away from the x axis. State the rule that you find.

y = (x + 1)^2(x - 2)

y = (x - 4)^3(x - 1)^2

y = (x - 3)^2(x + 4)^4
 
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Agreed with micromass, but here's a hint. Look at the numbers carefully.
 
For graphing you can use "Microsoft Mathematics". Its really a awesome software.
Give it a try. :smile:
 
okay well i tried to do it

is this correct?

x intercept y=0

y = (x + 1)^2(x - 2)
0 = (x + 1)^2(x - 2)
(x + 1)^2 = 0 =====> x + 1 = 0 =====> x = -1 (-1 , 0)
x - 2 = 0 =====> x = 2 (2 , 0)

y = (x - 4)^3(x - 1)^2
0 = (x - 4)^3(x - 1)^2
(x - 4)^3 = 0 ====> x - 4 = 0 =====> x = 4 (4 , 0)
(x - 1)^2 = 0 ====> x - 1 = 0 ====> x = 1 (1 , 0)

y = (x - 3)^2(x + 4)^4
0 = (x - 3)^2(x + 4)^4
(x - 3)^2 = 0 ====> x - 3 = 0 ====> x = 3 (3 , 0)
(x + 4)^4 = 0 ===> x + 4 = 0 ====> x = -4 (-4 , 0)
 
Am having trouble explaining it
 
From what I understand of your original post, you do not need to do all that work. It's simple, look at the graphs.

Hint: Take notice of the powers (not just by degree:wink:) to determine whether it goes right through or only touches.

EDIT: By the way, recall what multiplicity is.


The last function might be a little hard to view, but that should not affect your rule.:smile:

It might help to recognize how x2 and x3 look like.
 
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Yes it's correct, now try plugging in some numbers that make the factors negative :)