Graphs of Position & Kinetic Energy vs. Time: Solving U(x)=7J

AI Thread Summary
The discussion centers on a potential energy function U(x) = 4x^2, with a total energy of 7 J, leading to the graphs of position versus time and kinetic energy versus time. The position graph is identified as a sine curve due to the oscillatory motion of the particle, while the kinetic energy graph is described as a cos^2 function. The relationship between potential energy and kinetic energy is highlighted, noting that as potential energy increases, kinetic energy decreases, reaching zero when potential energy is at its maximum. The inquiry focuses on the mathematical reasoning behind using a cos^2 function instead of cos(2x) for the kinetic energy graph. Understanding the underlying principles of energy conservation is crucial for clarifying this relationship.
dmayers94
Messages
16
Reaction score
0

Homework Statement


A potential energy function is given by U(x) = 4x^2 and I found the total energy to be 7 J. They ask: Graph position vs. time and kinetic energy vs. time using this information and assume that the particle has an initial position of 0.

The Attempt at a Solution


I got the first part correct. It is just a sine curve because the object oscillates and is bounded by the total mechanical energy of 7 J. The second graph, KE vs. time, is a cos^2 function, but I'm not sure why. I know that as the potential energy increases, position increases, and when potential energy is at a max, KE is 0. The shape makes sense to me when I compare it to the position graph, but how did they come up with cos^2 mathematically? Why not cos(2x) instead?
 
Physics news on Phys.org
You need to work back from the main principles, to get the reason for using a cos^2 function. What is the main principle between energy, potential energy and kinetic energy? And what is the equation for this relationship?
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top