Graphs to find minimum days for meetings

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The discussion focuses on determining the minimum number of days required for eight committees to meet without overlapping members. A graph is constructed where each committee is represented as a vertex, and edges connect vertices that share members. The analysis reveals that at least four colors are necessary to color the graph, indicating that four days are needed for the meetings. The Appel-Haken Theorem supports this conclusion, confirming that three colors are insufficient due to the presence of a clique among certain committees. The final consensus is that four days are indeed the minimum required for all committees to meet without conflict.
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Homework Statement


Nine students A, B,..., I serve as members on eight committees, as follows.

Committee 1: A, B, C, D
Committee 2: A, C, D, E
Committee 3: B, D, F, G
Committee 4: C, F, G, H
Committee 5: A, H
Committee 6: H, I
Committee 7: G, H
Committee 8: E, I

Each committee is to meet for a day. No two committees with a member in common can meet on the same day. Use a colouring of a suitable graph to find the least number of days in which the meetings can take place.

Homework Equations


None

The Attempt at a Solution


Let 1,2...,8 be vertices on a graph and let an edge be between two vertices if those committees share a student. If an edge exists between two vertices, then those vertices must be coloured differently

I've drawn out the graph properly, and is 4 (the number of colours used to colour the graph) the minimum no of days needed for the committees to meet? I know that 4 can be used by the Appel-Haken Theorem. i can't see a way to colour the graph with only 3 colours.
Graph1.jpg
EDIT: just realized that 2 and 5 should be connected on the graph but it doesn't make any difference to the colouring.

thanks for any help :)
 
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Well, you have a clique (all nodes are connected to each other): \{1, 2, 3, 4\} so you need at least 4 colors, with 3 colors you can not even color your clique.
 
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