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What is the Colatitude Angle in Gravitation?
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Geostationary satellites maintain a fixed orbital radius and plane, crucial for their functionality. The discussion centers on determining the colatitude angle at which these satellites drop below the viewing horizon as one travels north or south. Participants seek clarification on the specific angle in question, referencing colatitude and related concepts. Visual aids are requested to enhance understanding of the angle involved. The conversation highlights the complexity of visualizing orbital mechanics in relation to Earth's curvature.
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gneill
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Geostationary satellites have a specific orbital radius, and orbit in a particular plane. The Earth is spherical. As you travel northwards (or southwards), at what colatitude will the satellite drop below the viewing horizon?
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gneill
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Colatitude: http://en.wikipedia.org/wiki/Colatitude
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gneill
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Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook.
Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water.
I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame?
I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
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