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anigeo
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if the Earth stops rotating , the value of 'g' will increase by Rω2 at the equator but will remain same at the poles.how does it happen?could you please explain me this?
Doc Al said:Imagine something was resting on a scale (such as a bathroom scale). What determines the reading of the scale? (Apply Newton's 2nd law.)
What didn't you understand?anigeo said:Can u be a little more precise.i could not get what u said.
When you figure out the answer at the equator, the answer at the poles will be clear.anigeo said:then doc, what about the poles?
i got the point clearly`.Doc Al said:When you figure out the answer at the equator, the answer at the poles will be clear.
The gravity at the equator is slightly less than at the poles due to the centrifugal force from the Earth's rotation. This causes the Earth to bulge slightly at the equator, making the distance from the center of mass slightly greater than at the poles.
The difference in gravity between the equator and the poles is very small, about 0.5% or 0.03 m/s². This means that a person who weighs 100 kg at the poles would weigh only 99.5 kg at the equator.
The Earth is not a perfect sphere, it is slightly flattened at the poles and bulging at the equator. This shape, combined with the Earth's rotation, causes the centrifugal force that results in a slightly lower gravity at the equator.
If there was no difference in gravity between the equator and the poles, the Earth would need to be a perfect sphere and not rotate. This would have significant impacts on our planet's climate, ocean currents, and even the length of a day.
The difference in gravity between the equator and the poles is so small that it does not significantly affect objects on Earth. However, it does play a role in the Earth's overall shape and rotation, which in turn affects global weather patterns and navigation systems.