Gravitational field strength problem- help needed

AI Thread Summary
The discussion revolves around calculating the gravitational pull of the Moon on Earth's oceans compared to Earth's gravitational pull on its own oceans. The relevant equations for gravitational field strength are provided, including g = GM / r^2. An attempt to solve the problem is made using the known values for the Moon's mass, radius, and gravitational field strength, but the calculations are deemed confusing. A suggestion is made to first calculate the gravitational field at Earth due to the Moon and then at Earth's surface due to Earth itself, followed by finding the ratio of these two values. The goal is to demonstrate that the Moon's gravitational influence is approximately 3 millionths of Earth's gravitational pull.
schroedinger4
Messages
1
Reaction score
0
gravitational field strength problem-urgent help needed

Homework Statement


Moon has a radius of 1740km, Mass of 7.35 x10^ 22kg, grav field strength of moon= 1.62Nkg^-1, distance from Earth to Moon is 380000km G=6.67x10^-11Nm^2kg^-2

The Moon's gravitational pull on the Earth causes the ocean tides. Show that the gravitational pull of the Moon on the Earth's oceans is approximately 3 millionths of the gravitational pull of the Earth on its oceans.


Homework Equations


g = GM / r^2 g = gs R^2 / r^2 where R= radius of planet, r = distance

The Attempt at a Solution


g = gs R^2 / r^2
1.62 = gs 1740x10^3 / 380000 x 10^3
(1.62 x 380000x10^3) / 1740 x 10^3 = gs

1/3000000= 3 x10^-6
3 x10^-6 x 9.81 = gs ?
Please help!
 
Last edited by a moderator:
Physics news on Phys.org


I don't think you've done it quite right, but you're not far off. You equations are a little confusing also.

I would first try to calculate the gravitational field at Earth due to the mass of the moon (as an equation). And then calculate the gravitational field at Earth's surface due to the mass of the Earth (as another equation). Then divide one by the other to get the ratio.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top