Gravitational Force on 0.64 kg Sphere in Space Shuttle

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SUMMARY

The gravitational force on a 0.64 kg sphere inside the space shuttle, which orbits 396.9 km above Earth's surface, can be calculated using the formula F = (G * M * m) / r^2. Given the mass of Earth (5.98 x 10^24 kg) and the radius of Earth (6.37 x 10^6 m), the correct distance (r) from the center of the Earth to the sphere is 6.37 x 10^6 m + 396.9 x 10^3 m, resulting in a gravitational force of approximately 5.57 N. The discussion highlights the importance of correctly defining the distance r as the total distance from the Earth's center to the object.

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nweis84
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I have this problem i have been trying to solve and can't seem to get it right. The question states:

The space shuttle is in orbit 396.9 km above the surface of the earth. What is the gravitational force on a 0.64 kg sphere inside the space shuttle?

mass Earth = 5.98x10^24 kg
radius of Earth = 6.37x10^6 m

I've tried using the equation F= (G*M*m)/r^2 and the answer i got was about 5.57 N

for the distance above Earth i converted the units and added them to the Earth's radius so I'm not sure what I could be doing wrong.

is it possible that i am using the wrong equation all together?
 
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r is defined as being the distance between the two point masses.

I might be wrong, but for this problem, would you not just use the distance from Earth as r?
 
F = GMm/r^2 , G is the universal gravity, M is mass of the object acting the force,
m is the mass of the object that the force is acted upon, r is the distance between the center of the Earth and the center of the object in space.
 

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