Gravitational Force on bathroom scales

AI Thread Summary
A person weighing 500N on Earth would weigh 714N on a planet with a gravitational field strength of 14 N/kg. The mass of the person is calculated to be 51 kg, which remains constant regardless of altitude. To find the radius of the planet, the gravitational force equation was applied, leading to a radius of approximately 2,160,789.4 km. For the weight at an altitude of 2.8 x 10^6 m, the same gravitational force equation should be used, factoring in the distance from the planet's center. The discussion emphasizes the distinction between mass and weight, clarifying that mass does not change with altitude.
Celer
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Hi all, I'm new here. So anyways, I have been studying for exams by going through my old tests, and I found a question from one of them that I can't solve...I hope someone can help me.

1. A person stands on a set of bathroom scales which have been calibrates in Newtons. The scales read 500N (assume 3 sig figs)
A)What would the reading be if the same person stood on the scales on a planet where the gravitational field strength, g is 14 N/kg?

B) If this planet had a mass of 7.0 x 10^24 kg, what would its radius be?

C) What mass would this person weigh at an altitude of 2.8 x 10^6 m above the planet's surface?

Homework Equations



Well I used the equations for
A)
F=mg

B)
F = G (mass planet) (mass object) / d^2

C) I don't know what equation to use...


So what I did:

for A) I used Fg=mg
so:

Fg = mg
500 = m (9.8)
m = 51

then I substituted for the planet.

Fg = m(14)
Fg = (51)(14)
Fg = 714

For B) I used F = G (mass planet) (mass object) / d^2
so,

Fg = 6.67 x 10^-9 *7.0x10^24 / d^2
d^2 = 4.669
d = 2160789.4 km

For C) given height, I don't know what equation to use.

So really, I don't know whether I used my equations correctly, so I would appreciate someone to point out my errors.
 
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Celer said:
C) What mass would this person weigh at an altitude of 2.8 x 10^6 m above the planet's surface?

Hi. The mass of a person should always be constant when he/she moves away from the surface of the planet. I believe the verb "weigh" here does not imply the weight of the person.
 
Celer said:
for A) I used Fg=mg
so:

Fg = mg
500 = m (9.8)
m = 51

then I substituted for the planet.

Fg = m(14)
Fg = (51)(14)
Fg = 714
Looks good.

For B) I used F = G (mass planet) (mass object) / d^2
so,

Fg = 6.67 x 10^-9 *7.0x10^24 / d^2
d^2 = 4.669
d = 2160789.4 km
Did you leave out the mass of the person?

For C) given height, I don't know what equation to use.
Use the same equation that you used for B. What would be the person's distance to the center of the earth?
 
Last edited:
Celer said:
C) What mass would this person weigh at an altitude of 2.8 x 10^6 m above the planet's surface?
I assume that the word mass was an error and that the question should read: What would this person weigh...
 
So, would the mass of the person be unchanged, at 51 kg? I am not sure on what you meant when you said use the same equation as "C".

Do you mean using Fg = mg? If so, how do I factor the given altitude into the equation?
 
Celer said:
So, would the mass of the person be unchanged, at 51 kg?
Yes.
I am not sure on what you meant when you said use the same equation as "C".
Oops... I meant: Use the same equation as used in "B".
 
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