- #1
tak08810
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Homework Statement
Suppose Earth were a nonrotating uniform sphere. As a reward for earning the highest lab grade, your physics professor chooses your laboratory team to participate in a gravitational experiment at a deep mine on the equator. This mine has an elevator shaft going 11.8 km into Earth. What would be the loss in weight at the bottom of this deep shaft for a student who weighs 750 N at the surface of the Earth?
Homework Equations
F = G Mm/R^2
The Attempt at a Solution
Well from the beginning, the problem confuses me because wouldn't your weight increase if you go deeper into the earth? Since that means R would be decreased?
Anyways, plugging in the values for M (ignoring m since it's so small in comparison) as 5.98 * 10^24 kg, R as (6380 kg - 11.8 km), and G as 6.67 * 10^-11 Nm^2/kg^2, I get a value of 9.8354... Then I divide that by gravity on the surface (9.8 m/s^2) to find how much the weight will increase. However, I cannot get the right answer!
Submission # Try Submitted Answer
1 Submission not graded. Use more digits. 2.8 N
2 Incorrect. (Try 1) 2.79 N
3 Incorrect. (Try 2) -2.79 N
4 Submission not graded. Use more digits. 3 N
5 Incorrect. (Try 3) 3.00 N
6 Submission not graded. Use more digits. 3. 5N
7 Submission not graded. Use more digits. 3. 5 N
8 Incorrect. (Try 4) 2.77 N
9 Incorrect. (Try 5) -2.77 N
10 Incorrect. (Try 6) 2.78 N
11 Incorrect. (Try 7) -2.78 N
Thank you for any help!