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For example, if I lift at 1.05G, at the surface, Earth's gravity will reduce my force by 9.80 m/s

^{2}, and my resultant force will be 0.05G (0.49 m/s

^{2}). However, at an altitude of 160km (low Earth orbit), Earth's gravity will be only 9.33 m/s

^{2}, so my resultant force will be 0.96 m/s

^{2}. At 400 km altitude (Int'l Space Station), Earth's gravity is reduced further, to only 8.68 m/s

^{2}, making my resultant force 1.61 m/s

^{2}. If I theoretically lift to geosynchronous orbit, 35,800 km, Earth's pull reduces to 0.22 m/s

^{2}. So the difficulty I'm having is a), what is my instantaneous acceleration at specific altitudes (such as LEO or ISS altitudes, or every 1000km up to geo - and I'm pretty sure I have this equation, from sqrt(current acceleration*distance travelled)), and b) how long will it take? I can figure this for consistent acceleration, but as you see, this isn't the case here.

Any help you can give with the equations would be very useful - otherwise, I'll have to resort to fair approximations, which I'd rather not do. And yes, I had calculus, but I haven't used it for several decades ... Thanks ... :-)