Gravitational Potential at a Midpoint: What is the Solution?

3 replies · 2K views · last reply
pyman999
Messages
7
Reaction score
0

Homework Statement


Physics exam question diagram: two masses m separated by distance r, with point P at the midpoint, and a table of four answer options (A to D) listing gravitational field strength and gravitational potential at P.


Homework Equations


g = G*M / r^2, where g is the gravitational field strength, G is the gravitational constant, M is the mass of the attracting body, r is the distance from the center of mass of the body.
V = -G*M / r, where V is the gravitational potential.

The Attempt at a Solution


For the gravitational field strength, as P is at a midpoint, we can say that r is 1/2*r, and as the masses are also equal, G*M / 1/2*r^2 = G*M / 1/2*r^2 (as they are equal, and in opposite directions), and they will simply cancel to 0. Therefore, it can't be A or B.

For gravitational potential, again, the masses are equal, and r is 1/2*r, so -GM / 1/2*r = -GM / 1/2*r, they will again cancel to 0. However, the answer is apparently C, where gravitational potential is -4G*M / r? I can't see why.
 
In V = -G*M / r there are no vectors, only scalars. r is a distance in this formula.

(dividing by a vector is awkward...)
 
BvU said:
In V = -G*M / r there are no vectors, only scalars. r is a distance in this formula.

(dividing by a vector is awkward...)
I see, so then you're left with -2GM / r + -2GM / r, my mistake.
 
The problem statement should clarify that the potential "at infinity" is defined as zero. Otherwise the question is ambiguous - you can always add a constant value to the potential without changing physics.
Using this, you can rule out answer (D) simply from the fact that an object there would need energy to escape, therefore the potential there cannot be zero.