Gravitational Potential Energy

AI Thread Summary
The discussion focuses on calculating the speeds of two neutron stars as they approach each other under gravitational influence. The gravitational potential energy (GPE) is highlighted as a key concept, emphasizing that it can be converted into kinetic energy as the stars move closer. Participants clarify that the gravitational forces acting on each star should not be combined, as they are equal and opposite, resulting in zero net force. It is suggested that the problem is best approached using energy conservation principles rather than directly calculating forces. Overall, understanding the relationship between gravitational potential energy and kinetic energy is crucial for solving the problem effectively.
iamazombie911
Messages
1
Reaction score
0

Homework Statement


Two neutron stars are separated by a distance of 4.80 E 10 m. They each have a mass of 3.60 E 30 kg and a radius of 1.30 E 5 m. If they are initially at rest...
How fast is each star moving when their separation has decreased to half its initial value?
How fast is each star moving just before they collide?

Homework Equations


(G = Newton's Gravitational Constant (around 6.67*10^-11)[/B]
GPE = -G(m1)(m2)/r
Work = GravitationalForce*Distance = GPE
GravitationalForce = (G)(M1)(M2)/R^2

The Attempt at a Solution


Both forces from each planet are acting on each other, so I put the total gravitational force as double the equation. Multiplied by the given distance to get work/GPE, and then took that and subtracted the same equation, except with the distance halved. Don't really know where to go from here.
 
Physics news on Phys.org
First, you cannot add the two forces together like that. Adding those two forces produces zero, since they are just action and reaction of the same interaction.
Secondly, you cannot take the force to be constant over the distance. It will increase as they get closer.
For this question, it is easier to forget about forces and just think about energy.
 
haruspex said:
First, you cannot add the two forces together like that. Adding those two forces produces zero, since they are just action and reaction of the same interaction.
Secondly, you cannot take the force to be constant over the distance. It will increase as they get closer.
For this question, it is easier to forget about forces and just think about energy.

Remember that gravitational potential energy can be transferred into other energy types and that total energy at a given point will always be preserved and what haruspex said is true as I believe this problem is most easily solve by only taking the energy and change of energy type of the two bodies into account
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top