Gravitational potential question, nasty

AI Thread Summary
The discussion revolves around calculating the gravitational potential energy lost by a satellite falling from a height of 400,000 meters to Earth's surface, which is determined to be -6083 J. Participants debate how to derive the gravitational field value at that height, with emphasis on using the Earth's radius in calculations. The radius of the Earth is noted as a constant (approximately 6378.1 km) necessary for solving the gravitational field equation. There is uncertainty about whether the radius should be provided in the problem statement, as it typically would be in an exam setting. The conversation highlights the importance of understanding gravitational potential and the necessary constants for accurate calculations.
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Homework Statement


Values for the grav potential due to the Earth are given below:

dist from Earth's surface/m : grav potential/MJ kg-1
0 : -62.72
390 : -59.12
400 000 : -59.03
410 000 : -58.94
Infinity : 0

1. If a satellite of mass 700kg falls from a ht of 400 000m to the Earth's surface, how much potential energy does it lose?

2. Deduce a value for the Earth's grav field at a ht of 400 000m.

Homework Equations



g=F/m

grav potential, \phi=Work done/mass
=GMeMm/r


The Attempt at a Solution


1)I think I got out this part.

Ep= m(\Delta\phi)
=(-67.72--59.03)(700)
=-6083J

2) G=gMM/r2

RE: \phi= GM/r

therefore, g=\phi/r

But this r=Re + height?

And this is where I'm stumped.
 
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well at what height above the surface of the Earth are you trying to find g at? The total radius will be the radius of the earth+the height at which you are trying to find the g value for.
 
anubis01 said:
well at what height above the surface of the Earth are you trying to find g at? The total radius will be the radius of the earth+the height at which you are trying to find the g value for.

At a ht of 400 000m. But they did not give me the r of the earth. Do I need to find it?
 
the radius of the Earth is a physical constant, you can just look up the value (6378.1km) and use that to solve your equation.
 
anubis01 said:
the radius of the Earth is a physical constant, you can just look up the value (6378.1km) and use that to solve your equation.

I don't think you could do that. These questions usually give you everything you need to solve them..besides you wouldn't be able to do that in an exam..
 
So..anyone?
 
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