Gravity and Angular acceleration

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SUMMARY

The discussion centers on calculating the angular speed required for a lander to simulate Europa's gravity conditions using a rotating arm in an Earth satellite. The mass of Europa is 4.8E22 kg, and its diameter is 3138 km. The participants clarify that the centripetal acceleration must equal the gravitational acceleration at Europa's surface, leading to the equation ω = √(GM/R^2). A critical point raised is the need to convert Europa's diameter from kilometers to meters for accurate calculations.

PREREQUISITES
  • Understanding of angular velocity and its relationship to centripetal acceleration
  • Familiarity with gravitational force equations, specifically Newton's law of universal gravitation
  • Knowledge of unit conversions, particularly between kilometers and meters
  • Basic principles of rotational motion and its application in physics
NEXT STEPS
  • Study the derivation of centripetal acceleration formulas in rotational dynamics
  • Learn about the gravitational properties of celestial bodies, focusing on Europa
  • Explore the implications of angular speed in engineering applications, such as satellite design
  • Investigate the use of simulation tools for testing conditions on extraterrestrial surfaces
USEFUL FOR

Students in physics, aerospace engineers, and researchers interested in planetary exploration and gravitational simulations.

sreya
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Homework Statement



There is strong evidence that Europa, a satellite of Jupiter, has a liquid ocean beneath its icy surface. Many scientists think we should land a vehicle there to search for life. Before launching it, we would want to test such a lander under the gravity conditions at the surface of Europa. One way to do this is to put the lander at the end of a rotating arm in an orbiting Earth satellite.

If the arm is 5.25m long and pivots about one end, at what angular speed (in rpm) should it spin so that the acceleration of the lander is the same as the acceleration due to gravity at the surface of Europa? The mass of Europa is 4.8E22kg and its diameter is 3138 km.

\omega =_____rpm

Homework Equations



v=\omega r

\frac{GMm}{R^2}=a

T = \frac{2\pi}{\omega}

The Attempt at a Solution



\frac{GMm}{R^2}=a

\frac{mv^2}{R}=ma

\frac{\omega^2R}{a}

\omega=\sqrt{\frac{a}{R}}

\omega=\sqrt{\frac{GM}{R_{europa}^2*R_{sat}}}

\frac{60\omega}{2\pi} = x rpm

Edit: Figured out the problem. The diameter of Europa is given in Km, you have to convert it to meters. Stupid Mastering Physics...

Apparently that's not right though??
 
Last edited:
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sreya said:
\frac{GMm}{R^2}=a
... this is not correct: dimensions don't match.

Your reasoning is unclear - you seem to want to put the centripetal acceleration of the station centrifuge equal to the acceleration due to gravity at the surface of Europa.

Try writing centripetal acceleration in terms of angular velocity.
 
Sorry that should be
\frac{GMm}{R^2}=g_{europa}

Which "technically" is still acceleration but that wasn't clear
 
Still not correct.
Dimension still don't match.

Does the acceleration of gravity depend on the mass of the object falling?
Hint: leaning tower of Pisa.

What about writing centripetal acceleration in terms of angular velocity?
 

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