- #1
EV33
- 196
- 0
Homework Statement
[tex]\oint[/tex]xydx+x^2dy
C is the rectangle with vertices (0,0),(0,1),(3,0), and (3,1)
Evaluate the integral by two methods: (a) directly and (b) using green's theorem.
Homework Equations
The Attempt at a Solution
Evaluating the integral directly:
c1: y=0,x=t,dx=dt,dy=o {0[tex]\leq[/tex]t[tex]\leq[/tex]3}
c2: x=3, y=t, dx=0, dy=dt {0[tex]\leq[/tex]t[tex]\leq[/tex]1}
c3: y=1, dy=0, x=t, dx=dt {0[tex]\leq[/tex]t[tex]\leq[/tex]3}
c4: x=0, dx=0, y=t, dy=dt {0[tex]\leq[/tex]t[tex]\leq[/tex]1}
So I got c1 and c4 being the integral of zero which is just zero.
Then for c2 and c3...
[tex]\int[/tex]9dt {t:0[tex]\leq[/tex]t[tex]\leq[/tex]1} +[tex]\int[/tex]tdt {t:0[tex]\leq[/tex]t[tex]\leq[/tex]3}=27/2Then trying to use green's theorem:
[tex]\int[/tex][tex]\int[/tex]xdydx=[tex]\int[/tex]xdx=9/2
{y:0[tex]\leq[/tex]y[tex]\leq[/tex]1}
{x:0[tex]\leq[/tex]x[tex]\leq[/tex]3}
I am not sure where I messed up but I know I did because both of my answers should be the same. If someone could point me in the right direction, it would be much appreciated. Thank you for your time.