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Homework Help: Green's Theorem and polar coordinates

  1. Dec 10, 2009 #1
    1. The problem statement, all variables and given/known data
    Using Green's Theorem, (Integral over C) -y^2 dx + x^2 dy=____________
    with C: x=cos t y=sin t (t from 0-->2pi)

    2. Relevant equations
    (Integral over C) Pdx + Qdy=(Double integral over D) ((partial of Q w.r.t. x)-(partial of P w.r.t. y))dxdy


    3. The attempt at a solution

    I'm stuck from here. I remember the professor said to use polar coordinates which makes sense to get the limits on D, but how do I convert the integral (-y^2 dx + x^2 dy) to polar?

    In my method I go from the original integral over C to (double integral over D) 2x+2y dxdy. I convert this to polar to get limits on D and I get (integral from 0 to 2pi)(integral from 0 to 1) 2rcos(theta)+2rsin(theta)*r*dr*d(theta). Once you calculate all of this you get 0 which I don't believe is correct. Any help?
     
    Last edited: Dec 10, 2009
  2. jcsd
  3. Dec 10, 2009 #2

    LCKurtz

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Why don't you think 0 is correct? It's quite a nice number, one of my favorites, actually.:smile:
     
  4. Dec 10, 2009 #3

    Mark44

    Staff: Mentor

    People sometimes want answers in round numbers. You can't get any rounder than zero.:smile:
     
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