Guided proof to the isomorphism theorems.

In summary, the conversation discusses the concept of homomorphisms and epimorphisms between groups and their normal subgroups. The main focus is on proving the existence of a unique mapping between quotient groups if and only if the subgroup is contained in the image of the original homomorphism. The proof involves showing that the composite of the quotient epimorphisms and the original homomorphism is a well-defined map and that the subgroup must be in the kernel for this to be true.
  • #1
*melinda*
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0

Homework Statement


Let [itex]G_1[/itex] and [itex]G_2[/itex] be groups with normal subgroups [itex]H_1[/itex] and [itex]H_2[/itex], respectively. Further, we let [itex]\iota_1 : H_1 \rightarrow G_1[/itex] and [itex]\iota_2 : H_2 \rightarrow G_2[/itex] be the injection homomorphisms, and [itex]\nu_1 : G_1 \rightarrow G_1/H_1[/itex] and [itex]\nu_2 : G_2/H_2[/itex] be the quotient epimorphisms.

Given that there exists a homomorphism [itex]\sigma : G_1 \rightarrow G_2[/itex], show that there exists a unique mapping [itex]\overline{\sigma} : G_1/H_1 \rightarrow G_2/H_2[/itex] such that [itex]\overline{\sigma} \circ \nu_1 = \nu_2 \circ \sigma[/itex] if and only if [itex]\sigma[H_1] \subset H_2[/itex]. If such a [itex]\overbar{\sigma}[/itex] exists, it is a homomorphism.


Homework Equations



There aren't any equations, as this is a proof.


The Attempt at a Solution



I know that since [itex]\nu_1[/itex] and [itex]\nu_2[/itex] are epimorphisms, they are surjective homomorphisms. So [itex]Im(\nu_1)=G_1/H_1[/itex] and [itex]Im(\nu_2)=G_2/H_2[/itex]. But I really don't see how to get this proof off the ground. Please help get me started.

The next question reads as follows.

Prove that there exists a unique mapping [itex]\sigma^{\prime} : H_1 \rightarrow H_2[/itex] such that [itex]\iota_2 \circ \sigma^{\prime} = \sigma \circ \iota_1[/itex] if and only if [itex]\sigma[H_1] \subset H_2[/itex]. If such a [itex]\sigma^{\prime}[/itex] exists, it is a homomorphism.
 
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  • #2
Let s=sigma, v=v_1 and w=v_2, cos I want to do this without having to type in tex. The only place to start is with the composite ws, since that is a well defined map, and it goes from G_1 to G_2/H_2. This gives a map of G_1/H_1 if and only if H_1 is in the kernel of the map ws. Which is if and only if... That is existence. Uniqueness we'll come to in a second.
 

1. What are the isomorphism theorems?

The isomorphism theorems are a set of three theorems in abstract algebra that establish a fundamental connection between group theory and ring theory. They provide a framework for understanding the structural properties of groups and rings, and allow for the simplification of complex algebraic problems.

2. Why are the isomorphism theorems important?

The isomorphism theorems are important because they provide a powerful tool for analyzing and manipulating mathematical structures. They allow us to identify and understand the underlying structure of groups and rings, and provide a systematic way to compare different groups and rings.

3. What is a guided proof?

A guided proof is a step-by-step demonstration of a mathematical theorem or concept, often with explanations and commentary to help the reader understand the reasoning behind each step. It is a useful tool for learning and understanding complex mathematical concepts, such as the isomorphism theorems.

4. How can the isomorphism theorems be applied in real-world situations?

The isomorphism theorems have numerous practical applications, particularly in areas such as coding theory, cryptography, and quantum mechanics. They can also be used to solve problems in fields such as engineering, economics, and computer science.

5. Are there any limitations to the isomorphism theorems?

While the isomorphism theorems are powerful tools, they do have some limitations. They only apply to certain types of mathematical structures, such as groups and rings, and may not be applicable to other areas of mathematics. Additionally, the theorems may not always provide a complete solution to a problem and may require additional techniques to fully solve a given problem.

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