Gymnast Equilibrium: Tension Calc.

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The discussion focuses on calculating the tension in the support ropes of a gymnast hanging from rings at a 5-degree angle to the vertical. The gymnast's mass is 65.0 kg, leading to a downward force of 637 N (65 kg multiplied by 9.8 m/s²). The equilibrium condition is established by setting the sum of the upward forces equal to the downward forces. The tension in each rope is calculated to be approximately 320 N. The solution is confirmed as correct by the participants in the discussion.
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[SOLVED] Gymnast equilibrium

Homework Statement


A gymnast of mass 65.0kg hangs from two fixed rings as shown in the diagram.
The gymnast is stationary and the support ropes make an angle of 5.0degrees to the vertical.

Calculate the tension in each of the support ropes.

http://img401.imageshack.us/img401/8334/gymnastpu6.jpg

Homework Equations


<br /> \sum {F_{up} } = \sum {F_{down} } <br />

The Attempt at a Solution


Well I have drawn a free body diagram.
Is this attempt correct?

<br /> \begin{array}{l}<br /> \sum {F_{up} } = \sum {F_{down} } \\ <br /> 2\left[ {T\cos 5} \right] = 65 \times 9.8 \\ <br /> \Rightarrow T = 3.20 \times 10^2 N{\rm} \\ <br /> \end{array}<br />
in each rope

Thanks in advance
Steven.
 
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Absolutely.
 
thanks for clearing that up :)

Steven
 
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