Half Angle Formula: Solving the Homework Statement

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The discussion centers on the derivation of the half-angle formulas for sine and cosine. The user seeks clarification on how the identities sin²θ = (1 - cos2θ)/2 and cos²θ = (1 + cos2θ)/2 relate to the half-angle formulas sin(θ/2) = √((1 - cosθ)/2) and cos(θ/2) = √((1 + cosθ)/2). The key insight is that by substituting θ with 2θ in the half-angle formulas, the identities for sin²θ and cos²θ are derived. This connection highlights the relationship between the half-angle and double-angle formulas in trigonometry. The user expresses realization and gratitude for the clarification.
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Homework Statement



Can someone please explain how my book got sin^{2} \theta = \frac{1-cos2\theta}{2} and cos^{2}\theta = \frac{1+cos2\theta}{2}

As I thought the half angle formula's were sin \frac{\theta}{2} = \sqrt{\frac{1-cos\theta}{2}}

cos\frac{\theta}{2} = \sqrt\frac{1+cos\theta}{2}}

So how can it also be the top one's aswell?

Thanks.
 
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Replace θ with 2θ.
 
Doc Al said:
Replace θ with 2θ.


Oh I see, can't believe I missed that.

Thanks.
 
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