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## Homework Statement

A projectile's horizontal range on level ground is R=v

_{0}

^{2}sin2[tex]\vartheta[/tex]/g. At what launch angle or angles will the projectile land at half of its maximum possible range

## Homework Equations

## The Attempt at a Solution

All I know is that a projectile goes the furthest when the angel is 45

^{o}. I know I have to say 1/2R = the whole thing but I am not sure what to do to solve this. There are two answers. Thanks for any help! I appreciate it.