A projectile's horizontal range on level ground is R=v02sin2[tex]\vartheta[/tex]/g. At what launch angle or angles will the projectile land at half of its maximum possible range
The Attempt at a Solution
All I know is that a projectile goes the furthest when the angel is 45o. I know I have to say 1/2R = the whole thing but I am not sure what to do to solve this. There are two answers. Thanks for any help! I appreciate it.