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Hall Effect and Drift Velocity

  1. Oct 27, 2008 #1
    1. The problem statement, all variables and given/known data
    A thin metal film of length 1.00 cm, width of 0.250 cm, and thickness of 29.0 micrometers is used to measure the Hall effect. A current of 2.60 A is maintained along the length of the sample. The Hall voltage of 16.0 microVolts is detected across its width, when a magnetic field of 2.00 Tesla is applied normal to the film.
    Calculate the drift velocity of the charge carriers.


    2. Relevant equations
    Vh = IB/ned
    I=neAVd

    Vh = Hall Voltage
    Vd = Drift Velocity
    I = Current
    B = Magnetic Field
    n = Number of electrons
    e = Charge of particle
    A = area
    d = Thickness of film

    3. The attempt at a solution
    Using equation 1 I got n = IB/Vhed
    Then I plugged that into equation 2 and solved for Vd but this answer is incorrect.

    Any help would be greatly appreciated! Thanks
     
  2. jcsd
  3. Oct 27, 2008 #2
    The drift velocity is what makes the magnetic field, so I think the equation should be:

    q Vh *width = q Vd B

    So Vd = Vh * width/B
     
  4. Oct 27, 2008 #3
    Using that equation I got Vd = 16e-6 * 0.0025 / 2.00 = 2.00e-8 m/s

    This answer was incorrect though.
     
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