What is the equation of motion for the mass in this system?

In summary: The mass has a displacement x and an applied force F. The equation of motion is then m\ddot x = A - Bx.A = 80x - 30BB = -10x
  • #1
Karol
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Homework Statement


A mass of 0.1 kg has 2 springs of length 20 cm attached to each side, like in the drawing. they are loose. one has a constant of 50 [N/m] and the other 30. The system is between 2 walls 10 cm distant from each spring.
At the second stage the springs are tied each to the nearest wall. the system stabilizes and the springs have different length. what is the length of each spring.
This is the first part of a question, but i got stuck.

Homework Equations


Spring force: $$F=kx$$

The Attempt at a Solution


At first i marked with x the distance the k=50 spring stretches. of course it is tied to the wall but i drew it apart in order to clarify. in this notation the k=30 spring stretches 0.1 meter + (0.1-x):
##50x=30\left[ 0.1+\left( 0.1-x \right) \right] \Rightarrow x=0.075##
And it is correct. but then i used an other notation, like in the second drawing, where x is the distance from the wall and tried:
##50(0.1-x)=30(0.1+x)##
And it's wrong, i can't understand why
 

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  • #2
Karol said:

Homework Statement


A mass of 0.1 kg has 2 springs of length 20 cm attached to each side, like in the drawing. they are loose. one has a constant of 50 [N/m] and the other 30. The system is between 2 walls 10 cm distant from each spring.
At the second stage the springs are tied each to the nearest wall. the system stabilizes and the springs have different length. what is the length of each spring.
This is the first part of a question, but i got stuck.

Homework Equations


Spring force: $$F=kx$$

The Attempt at a Solution


At first i marked with x the distance the k=50 spring stretches. of course it is tied to the wall but i drew it apart in order to clarify. in this notation the k=30 spring stretches 0.1 meter + (0.1-x):
##50x=30\left[ 0.1+\left( 0.1-x \right) \right] \Rightarrow x=0.075##
And it is correct. but then i used an other notation, like in the second drawing, where x is the distance from the wall

[itex]x[/itex] is the distance from the left wall to what? Your diagrams are not exactly clear.

and tried:
##50(0.1-x)=30(0.1+x)##
And it's wrong, i can't understand why

You will get that equation by taking [itex]x[/itex] to be the displacement of the mass from its initial position, with positive [itex]x[/itex] in the direction of the spring with constant 50 N/m.
 
  • #3
It is best to solve problems symbolically, and to only plug in numbers at the very end. That way you can see at each step what is going on.

Try doing that with your second method.
 
  • #4
pasmith said:
You will get that equation by taking [itex]x[/itex] to be the displacement of the mass from its initial position, with positive [itex]x[/itex] in the direction of the spring with constant 50 N/m.
Yes, this is another way to look at my second method. your x, the displacement of the mass, is equal to my x, the distance to the wall. of course the mass moves, but to me it was clearer to visualize with the mass fixed.
So, this equation:
##50(0.1-x)=30(0.1+x)##
Describes the mass's displacement x as you said but it's wrong.
 
  • #5
Karol said:
Yes, this is another way to look at my second method. your x, the displacement of the mass, is equal to my x, the distance to the wall. of course the mass moves, but to me it was clearer to visualize with the mass fixed.
So, this equation:
##50(0.1-x)=30(0.1+x)##
Describes the mass's displacement x as you said but it's wrong.

Solving that gives [itex]80x = 2[/itex], so [itex]x = 1/40 = 0.025[/itex]. The extension in the spring with constant 50 is then [itex]0.1 - x = 0.075[/itex], in agreement with your first method.
 
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  • #6
Now continuing i have to show that the combined spring constant, or as the question says the effective force constant (i hope it's the same as i said) is 80.
But to my understanding it's 30 since one spring works against the other
 
  • #7
Karol said:
Now continuing i have to show that the combined spring constant, or as the question says the effective force constant (i hope it's the same as i said) is 80.
But to my understanding it's 30 since one spring works against the other

Work out the equation of motion of the mass, and express it in the form [tex]
m\ddot x = A - Bx.
[/tex] What is [itex]B[/itex]?
 

What is a harmonic oscillator 3?

A harmonic oscillator 3 is a type of physical system that exhibits periodic motion, where the restoring force is directly proportional to the displacement from equilibrium position. It can be represented by a mass attached to a spring, a pendulum, or an electric circuit.

What is the equation for a harmonic oscillator 3?

The equation for a harmonic oscillator 3 is F = -kx, where F is the restoring force, k is the spring constant, and x is the displacement from equilibrium position. This equation is known as Hooke's law.

What is the difference between a harmonic oscillator 3 and a simple harmonic oscillator?

A harmonic oscillator 3 is a more general form of a simple harmonic oscillator, where the restoring force is not only proportional to the displacement but also to the velocity and acceleration. This means that a harmonic oscillator 3 can exhibit more complex motion patterns compared to a simple harmonic oscillator.

What are the applications of harmonic oscillator 3?

Harmonic oscillator 3 is a fundamental concept in physics and has various applications in different fields. Some examples include oscillating electric circuits in electronics, molecular vibrations in chemistry, and pendulum clocks in timekeeping.

How is the energy of a harmonic oscillator 3 related to its frequency?

The energy of a harmonic oscillator 3 is directly proportional to its frequency. This means that a higher frequency results in a higher energy state, while a lower frequency results in a lower energy state. This relationship is described by the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency.

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