Have a pretty basic chem problem about lights and radiation

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To determine the minimum energy the instrument is sensitive to, the energy of a single photon can be calculated using the formula E = (Planck's constant * speed of light) / wavelength. Given the wavelength of 8.065 × 10^-8 m, this equation provides the energy per photon. Once the energy of one photon is found, it can be multiplied by the total number of photons detected, which is 9450, to find the total energy in joules. This approach allows for the correct calculation of energy in scientific notation. The discussion emphasizes the importance of using the correct formula and understanding the relationship between photons and energy.
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An instrument can detect 9450 photons of light of wavelength of 8.065 × 10^-8 m. What is the minimum amount of energy in J to which the instrument is sensitive? Express answer in scientific notation..

i have tried to use the e = (planck's constant) ( speed of light ) / (wavelenghth) but i am not sure how the photons figure is used
 
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If one photon carries 10-18 J of energy, how much energy is carried by two identical photons?
 
where did you get 10^-18
 
Nowhere, it is not directly related to the question. I could as well ask "If one photon carries 1018 J of energy, how much energy is carried by two identical photons?", although that'll be quite a photon :bugeye:
 
so how would i know how much energy does each photon carry
 
You have already listed equation that allows calculation of the energy of a single photon.
 
so would i plug the wavelength into the equation and multiply by the number of photons and get my answer?
 
Exactly.
 
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