Find Head of Vector [a,b,c] with Length 3 in Same Direction as [−3,−4,12]

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To find the head of vector [a,b,c] with a length of 3 in the same direction as vector a=[-3,-4,12], the direction ratios must match the cosine of the angles derived from vector a's magnitude of 13. The calculations yield the equations: a/3 = -3/13, b/3 = -4/13, and c/3 = 12/13. The user believes their derived values for a, b, and c are correct based on a similar problem but is confused by differing results from the book. Clarification is sought on the correct values and potential errors in the approach. The discussion highlights the importance of verifying calculations when results differ from established answers.
PiRsq
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The question asked me to find the head of a vector [a,b,c] whose length is 3 and is in the same direction as vector
a=[-3,-4,12]

So I found the follwing:

Let vector x be the unknown vector

|a|=13
|x|=3

Since they are both in the same direction, they both must have the same direction angles right?

So:

Cos alpha = -3/13 which is equal to a/3
Cos beta = -4/13 which is equal to b/3
Cos gamma = 12/13 which is equal to c/3

Then I got the values for a,b and c but the book shows me a different answer. What am I doing wrong here?
 
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What values did you get, and what does the book say?
 
I found my answer to be correct because I did a similar question and found my method to work. Thx though
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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