Heat Engine Cycle: Answers to (i), (ii) & (iii)

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Two reversible heat engines operate in series between a high-temperature source at 600°C and a low-temperature sink at 30°C, with equal efficiencies. The first engine rejects 400 kJ to the second, leading to calculations for the temperature at which heat is supplied to the second engine, the heat taken from the source, and the work done by each engine. The solutions indicate that the second engine receives heat at 241.3°C, the total heat taken from the source is 679.1 kJ, and the work done by each engine is 279.1 kJ and 164.4 kJ, respectively. To solve these problems, it's essential to apply the Carnot cycle equations and draw a diagram to visualize the heat and work flows. Understanding the Carnot efficiency equation is crucial for accurate calculations.
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Two reversible heat engines operate in series between a source at 600C and a sink at 30C.
If the engines have equal efficiencies and the first rejects 400 kJ to the second, calculate:
(i) the temperature at which heat is supplied to the second engine;
(ii) the heat taken from the source;
(iii) the work done by each engine.
Assume that each engine operates on the Carnot cycle.
Answers: 241.3C; 679.1 kJ; 279.1 kJ and 164.4 kJ.


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First of all draw the engine diagram showing the heat and work flows. What is the equation to get the carnot efficiency of an engine?
 
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