Heat injection and work during Rankine cycle

In summary, the Rankine cycle consists of four processes, two adiabatic and two isobaric, but the work done during the isobaric processes is ignored. This is because the work done there is simply the work that the steam does to make room for itself. The physical activity that results in work being done is the addition of heat while keeping pressure constant, which causes the volume to increase. However, in the Rankine cycle, most of the heat goes into vaporization or condensation, which is why we say there is no work done during these processes. The open system version of the first law of thermodynamics is also relevant to this discussion.
  • #1
GwtBc
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I have been researching the Rankine cycle. I know that it consists of two adiabatic and two isobaric processes. However, I'm not entirely sure why we ignore the work done during the isobaric processes (this seems to be the case in the analysis I'm looking at). Is that because the work done there is simply the work that the steam does to make room for itself? (and vice versa)
 
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  • #2
In these processes heat is just being added or removed at constant pressure . Where is there any physical activity that results in work being done ?
 
  • #3
Nidum said:
In these processes heat is just being added or removed at constant pressure . Where is there any physical activity that results in work being done ?
You add heat and pressure is kept constant, i.e. volume increases. That is usually the physical process that results in work being done. But here most of the heat goes into vaporization/condensation. Is this why we say that there is no work done during these processes?
 
  • #4
Are you familiar with the open system (control volume) version of the 1st law of thermodynamics?
 
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