Heat Transfer between two temperatures

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Discussion Overview

The discussion revolves around calculating energy loss due to heat transfer between two areas with significantly different temperatures, specifically in the context of maintaining a cold room at -25°C while a door opens to a warmer area at +15°C. Participants explore the appropriate methods for calculating energy loss and consider practical implications of door design and usage.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Experimental/applied

Main Points Raised

  • One participant questions whether the convective heat transfer formula is suitable for calculating energy loss in this scenario.
  • Another participant suggests that redesigning the door system may be more effective than relying solely on calculations for cooling requirements.
  • A participant mentions a specific claim that opening the door costs 500 kWh, expressing uncertainty about how to verify this statement.
  • One suggestion involves conducting an experiment to measure power usage with the door closed versus during normal operations to assess energy loss.
  • A request for clarification on how often the door is open during normal working hours is posed to better understand the situation.

Areas of Agreement / Disagreement

Participants express differing views on the best approach to address the energy loss issue, with some emphasizing the need for experimental verification while others focus on the design of the door system. No consensus is reached regarding the most effective method for calculating energy loss.

Contextual Notes

Participants note that there is insufficient information provided to give precise answers, and the discussion highlights the complexity of accurately calculating energy loss in this scenario.

Who May Find This Useful

Individuals interested in thermal dynamics, energy efficiency in cold storage, and practical applications of heat transfer principles may find this discussion relevant.

ShimaParty
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Hi,

I'm trying to calculate energy loss between two areas. One area is -25C and another is +15. The contact area(door) is 20m^2. Is convective heat transfer formula the right way to calculate it, or what should I use? I want to find out the how many kW I need to keep cold area at -25 when the door is open.

Thank you
 
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Sounds like a lost cause from your description so far .

If this is a cold room type problem the solution may lie more in redesigning the door system than in calculations and installation of high power cooling equipment .

Anyway not enough information to give proper answers . Please describe the problem in more detail .
 
Nidum said:
Sounds like a lost cause from your description so far .

If this is a cold room type problem the solution may lie more in redesigning the door system than in calculations and installation of high power cooling equipment .

Anyway not enough information to give proper answers . Please describe the problem in more detail .

I agree that the solution lies in door system, but the payback on that door system depends on how much do I lose by not doing it.
I appreciate there might be no way how to easily calculate it.

My problem is: I've got a site that is cooled down to -25C. I was told that opening the door(10.2m^2) to the yard(+15C) costs me 500KWh , but I've got no way of verifying that statement. Is there a way how to verify that or not?

Thank you
 
It may be possible to come up with an answer experimentally .

You will have a power usage meter supplied by the power company .

Keep the door permanently closed for at least 24 hours - maybe during a holiday period . Measure the power used during this period .

Measure the power used on a normal working day with doors opening and closing for the same period .

See how much difference there is in power usage .

Ideally repeat the experiment a few times .

The above will give reasonable answers if the cold room uses most of the power coming into your site .

You can do a very accurate assesment if you privately install a power usage meter specifically for the cold room .
 
What fraction of the time is the door open for during normal working ?
 

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