Heat transfer, single and double paned window. Stove and pot.

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Discussion Overview

The discussion revolves around heat transfer calculations for single and double-paned windows, as well as the thermal dynamics of a pot on a stove. It includes theoretical and practical aspects of thermal conductivity, resistance, and temperature calculations in different materials.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates heat loss through a single pane of glass and a double-paned window using thermal conductivity and temperature differences.
  • Another participant points out an error in the resistance calculation for the double-paned window, suggesting the total resistance value should be .424 instead of .0424, leading to a different heat transfer rate.
  • Discussion includes the impact of air resistance in double-paned windows and mentions that real-life scenarios would also need to consider radiation effects and gas motion between panes.
  • Participants calculate the temperature of the bottom of a pot made of aluminum and copper when heated, with results showing very close temperatures for both materials.
  • One participant expresses uncertainty about the calculations, questioning the significant difference in heat loss values.

Areas of Agreement / Disagreement

There is disagreement regarding the correct total resistance value for the double-paned window calculations, with one participant asserting a correction. The discussion on the pot's temperature appears to be agreed upon as correct by at least one participant.

Contextual Notes

Participants mention additional factors such as radiation and gas motion that could affect heat transfer but do not resolve how these factors would quantitatively influence the calculations presented.

Who May Find This Useful

Individuals interested in thermal dynamics, heat transfer calculations, and practical applications in engineering or physics may find this discussion relevant.

Ulyaoth
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A glass window 1m x 2m and .005m thick has thermal conductivity of 1.4W/m K. Inner surface temp of 15C and outside of -20C, what is the heat loss through the glass.

double paned construction two panes separated by .01m, if glass surfaces are 10C and -15C, with air thermal conductivity of .024W/m K

q''= -k dT/L
q’’= 1.4W/m•K((288K-253K)/(.005m)), q’’=9800W/m2, q=9800W/m2 • 2m2 = 19600W

Double Paned: Rtot = L/kg+L/ka+L/kg,
Rtot = (.005m)/(1.4W/(m•K))+(.010m)/(.024W/(m•K))+(.005m)/(1.4W/m•K)
Rtot=0.424K/W,
q=ΔT/Rtot, q=(283K-253K)/(.0424K/W), q=70.75W


It just seemed like too big of a difference to be the correct answer. Just one more I wasn't sure of.

The 5mm thick bottom of a 200mm diameter pan may be copper(k = 390W/m K) or aluminum (240W/m K). When used to boil water the surface of the bottom exposed to the water is nominally 110C. IF the heat transferred from the stove to the pot is 600W, what is the temperature of the surface in contact with the stove for the two materials
A=0.031416m2, q''=19100W
q=k(Tbottom-Tin)/L (q•L)/k+Tin=Tbottom,alum
Tbottom,alum=(19100W/m^2(.005m))/(240W/m•K)+383K = 383.398K
Tbottom,copper=(19100W/m^2(.005m))/(390W/m•K)+383K = 383.245K


Again, just wasn't sure, it seemed the numbers were too close.
 
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q=ΔT/Rtot, q=(283K-253K)/(.0424K/W), q=70.75W

You have a slight error in the above. It should be 82.6. The .0424 should be .424.

The huge difference comes from the additional resistance of the air. Look at the ratios of k/dx for air gap and for a pane of glass. The difference is large.

In a real life problem, you also have the radiation factor where the hotter pane loses heat to the cooler pane. It has an effect but is not considered in this problem. To complicate the issue further, there is motion of the trapped gas between the panes that further enhances the heat transfer.
 
Second part dealing with the pot on the stove is correct.
 
Thank you, just wanted to make sure I had the right idea for the problem.
 

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