(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The height of a helicopter above the ground is given byhis in meter andtis in seconds. After 2.00 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground?

2. Relevant equations

v_{xf}= v_{xi}+a_{x}*t

v_{x,avg}= (v_{xi}+v_{xf})/2

x_{f}=x_{i}+1/2(v_{xi}+v_{xf})*t

x_{f}=x_{i}+v_{xi}*t+1/2a*t^{2}

v_{xf}^{2}= v_{xi}^{2}+2*a(x_{f}-x_{i})

3. The attempt at a solution

What I did was put 2 sec into the height equation, then use the above bolded equation, where i put the constant of gravit as the acceleration and v_{xi}as 0 and x_{i}as h(2) and x_{f}as 0, but the webassign online says i got it wrong and i did it like 5 times. Can someone tell me their thought process and the answer?

Thanks!

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# Helicopter Problem!

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