1. The problem statement, all variables and given/known data The height of a helicopter above the ground is given by h is in meter and t is in seconds. After 2.00 s, the helicopter releases a small mailbag. How long after its release does the mailbag reach the ground? 2. Relevant equations vxf= vxi+ax*t vx,avg= (vxi +vxf)/2 xf=xi+1/2(vxi +vxf)*t xf=xi+vxi*t+1/2a*t2 vxf2= vxi2+2*a(xf-xi) 3. The attempt at a solution What I did was put 2 sec into the height equation, then use the above bolded equation, where i put the constant of gravit as the acceleration and vxi as 0 and xi as h(2) and xf as 0, but the webassign online says i got it wrong and i did it like 5 times. Can someone tell me their thought process and the answer? Thanks!