Why Does a Helium Balloon Tilt Forward in an Accelerating Car?

AI Thread Summary
A helium balloon tilts forward in an accelerating car due to the pressure differences created by the movement of air inside the vehicle. As the car accelerates, air molecules are pushed toward the back, resulting in higher pressure at the rear and lower pressure at the front. This pressure differential exerts a force on the lighter-than-air balloon, causing it to move forward. The same principle applies when the car turns, causing the balloon to lean into the turn. Understanding these dynamics involves recognizing the buoyant forces and pressure variations in non-inertial frames.
HHveluj
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Homework Statement


Why is helium balloon in accelerating car tilting forward?

Homework Equations


The example that I think that I understand - is simple pendulum in accelerating car - and everything there is clear - g(effective)=g-A (all of them are vectors).

The Attempt at a Solution


So, the difference from the pendulum is only presence of buoyant force that's making baloon to float. So why is it tilting forward?

P.S. This question is in section 'Mechanics in Noninertial Frames', I'm not sure if it should be placed in this forum, but not advanced... Maybe the problem is harder than I imagine? Or easier?... :)
 
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Think first about what makes a helium balloon float in air. Think in terms of the forces acting on the balloon. Then think about what must happen to the air molecules in an accelerating car. Are they distributed in the same way as they are in a car that is not accelerating?
 
So, the only difference is that in case of balloon - it's lighter than air => the air will move to the back of the car and thus push baloon forward?...
 
HHveluj said:
So, the only difference is that in case of balloon - it's lighter than air => the air will move to the back of the car and thus push baloon forward?...

That is basically it. The balloon floats in still air because the pressure is higher on the bottom of the balloon than it is on the top. The pressure difference comes from the weight of the air between the top and bottom. In the accelrating car there will be a pressure difference because the air at the back of the car provides the force needed to accelerate all the air in front of it, and there is more air to push as you go farther back in the car. The pressure difference will be more than enough to accelerate the lighter than air ballon, so it will move forward relative to the car.

The same thing happens when the car goes around a turn. The balloon will lean into the turn.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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