- #1
Dustobusto
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Homework Statement
h(x) = f[g(x)]
h'(x) = f'[g(x)] * g'(x)
Homework Equations
h(x) = sin(-x)
The Attempt at a Solution
So, this one is pretty simple, except I just want to confirm something. When I do it it, it looks like this:
The derivative of sin = cos,
so you have
h(x) = cos(-x)
then you multiply the outside by g'(x). The derivative of -x is negative one. So it's
h(x) = cos(-x) * -1
h(x) = -cos(-x)
h'(x) = cos(x)
But the computer program bagatrix insists the final answer is
h'(x) = -cos(x)
Am I wrong, and if so, where did I go wrong?