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Homework Help: Helmholtz Coil

  1. Jul 28, 2008 #1
    1. The problem statement, all variables and given/known data

    The picture shows (there's supposed to be a pic) a Helmholtz coil consisting of two circular coaxial coils, each of 200 turns and radius R = 25.0 cm, separated by a distance s = R. The two coils carry equal currents i = 12.2 mA in the same direction. Find the magnitude of the net magnetic field at point P, midway between the coils.

    2. Relevant equations

    [tex]B(z)= \frac{\mu_0}{2 \pi} \frac{\mu}{z^3}[/tex]

    3. The attempt at a solution

    I thought this was a pretty straightforward question and did the following:

    [tex]\mu=NiA=(200)(12.2 \times 10^{-3} A)(\pi \times (0.25 m)^2) =4.79 \times 10^{-1} Am^2[/tex]

    [tex]B(z)= (\frac{1.26 \times 10^{-6}H/m}{2 \pi})( \frac{4.79 \times 10^{-1}}{(0.125m)^3})[/tex]
    [tex]=4.918 \times 10^{-5}T[/tex]

    Now, the magnetic force from both coils are in the same direction, so I multiplied the above answer with two and got

    [tex]\mbox{Force at P}=9.84 \times 10^{-5}[/tex]

    However, this doesn't seem to be correct according to the answers I have...Could you tell me where I went wrong please? I'm clueless.

  2. jcsd
  3. Jul 29, 2008 #2


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    Science Advisor
    Homework Helper

    Hi phyzmatix! :smile:

    (Thanks for the PM.)

    I get very confused about currents in coils.

    Is the area relevant? :confused:

    Anyway, there's a formula at http://en.wikipedia.org/wiki/Helmholtz_coil which … erm … looks nothing like yours! :redface:
  4. Jul 29, 2008 #3
    Cheers Tiny-Tim! There are no excuses here...I had that EXACT same page open in front of me last night and didn't notice that the answer was right there...Shows you that skimming too quickly isn't always the best way to approach things :redface:

    Sorry to have bothered you :redface:
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