Help can anyone answer my question

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The discussion centers around an experiment involving the boiling points of mixtures of two miscible liquids: trichloromethane and ethyl ethanoate, and hexane and propanone. For the trichloromethane and ethyl ethanoate mixture, the boiling point initially rises with increasing volume percentage of ethyl ethanoate, then drops, indicating a non-ideal solution behavior due to varying intermolecular attractions. In contrast, the hexane and propanone mixture shows a decrease in boiling point followed by a slight increase, suggesting different interactions between the components. The key takeaway is that the boiling point behavior of mixtures depends on whether they form ideal or non-ideal solutions, influenced by the attraction characteristics of the components involved.
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help!can anyone answer my question!

it is the experiment that i did in school!~
topic:boiling point with composition for different mixtures of two miscibe liquids


first: mixing trichloromethane and ethyl ethanoate
so the following is the result~
Volume of trichloromethane/cm3
10 10 10 10 5 2 0
Volume of ethyl ethanoate/cm3
0 2 5 10 10 10 10
Volume % of ethyl ethanoate
Boiling point/0C
60 65 70 68 67 66 63








by plotting boiling point against volume %of ethyl ethanoate . we can see the curve rise but after drop , so why this happen !~??/
can anyone explain in detail ?
help me please!~
 
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the boiling point of mixing hexane and propanone just opposite .
it's curve drop but rise slightly .
why ?
Volume of trichloromethane/cm3
10 10 10 10 5 2 0
Volume of ethyl ethanoate/cm3
0 2 5 10 10 10 10
Volume % of ethyl ethanoate
Boiling point/0C
67 52 49 54 52 57 59
 
It all depends on the type of solution, whether it is an ideal solution, non-ideal solution etc...this pertains to the attraction characteristics between the two components.

If it is a ideal solution, then the mixtures will exhibit boiling point elevation with the higher boiling points exhibited by the mixture rather the the individual pure solutions (this is what you have with the trichloromethane and ethyl ethanoate), quite different for the vice versa situation.

I'll try to explain it in more detail if you're still wondering about it.
 
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