Help Conserv. of Energy Momentum is Driving Me Crazy

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To determine the height from which a 100 g granite cube should be released to give a 215 g steel cube a speed of 200 cm/s upon collision, the conservation of momentum and energy principles must be applied. The granite cube and steel cube can be treated as a single unit after the collision. The initial velocity of the granite cube before the collision can be calculated using momentum conservation equations. Subsequently, the distance traveled along the ramp can be determined using kinematic equations. The height can then be found by relating the ramp distance to the sine of the angle of the ramp.
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Homework Statement



A 100 g granite cube slides down a 35 degree frictionless ramp. At the bottom, just as it exits onto a horizontal table, it collides with a 215 g steel cube at rest.
How high above the table should the granite cube be released to give the steel cube a speed of 200 cm/s?

Homework Equations



Conservation of momentum and energy equations. I don't know if there are more?


The Attempt at a Solution



For momentum: .1v1=.1v1_f+.215v2_f

For energy: .1(9.81)h=.5(.1)v1_f^2+.5(.215)v2_f^2

I know I'm supposed to solve a system of equations, but I have way too many variables right now. What am I doing wrong? What should I do next?
 
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Have you done some sketches? Can you see a way of breaking this problem down into smaller parts?
 
Hi

Ill tell you the path to solve this. it seems that there is a lack of given data. to overcome that you have to do the following assumption.

after the collision the granite cube and the steel cube behaves as a single unit.

from the equations of conservation of momentum find the velocity of the granite cube before the collision.

then apply v^2=u^2+2as along the ramp. here v is the velocity of the granite cube before the collision, u=0. s is the distance traveled by the granite cube along the ramp.
to find a apply F=ma along the ramp.

finally s*sin35=the height you want

ragards
Ashanthi
 
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