tnutty
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Can Xor be distributive for all cases ?
ex,
(X xor Y)Z
=
XZ xor YZ in all cases?
ex,
(X xor Y)Z
=
XZ xor YZ in all cases?
The discussion centers on the distributive property of the XOR operation in Boolean algebra. Specifically, it questions whether the expression (X XOR Y)Z is equal to XZ XOR YZ in all cases. The participants reference the fundamental definition of XOR, A ⊕ B = ¬A B + A ¬B, to analyze both sides of the proposed equality. The consensus is that the distributive property does not hold universally for XOR.
PREREQUISITESStudents of computer science, mathematicians, and anyone interested in digital logic design or Boolean algebra concepts.