# Help finals tomorrow

PART B

## Homework Equations

$$P = \rho gh$$

## The Attempt at a Solution

Well I tried doing 412 = (1025)(9.8)h.. Divide by 10045 (9.8 x 1025). And ended up getting .041..
I found out that I need to use 412 x 105 for the pressure which I have no idea why.

Any help?

berkeman
Mentor

PART B

## Homework Equations

$$P = \rho gh$$

## The Attempt at a Solution

Well I tried doing 412 = (1025)(9.8)h.. Divide by 10045 (9.8 x 1025). And ended up getting .041..
I found out that I need to use 412 x 105 for the pressure which I have no idea why.

Any help?