Help find the force of compression

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SUMMARY

The discussion focuses on calculating the force of tension in a chain and the force of compression in a support bar, given a mass of 20.4 kg and an angle of 22 degrees. The gravitational force was calculated as Fgravity = mg = 20.4 * 9.8 = 200N. The tension was determined using the equation Tcos(90-22 degrees) - 200N = 0, resulting in a vertical component of T = 534N. The horizontal component was resolved to x = 495N, confirming the calculations for the forces involved.

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dani123
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Find the force of tension in the chain. Determine the force of compression in the support bar. Be sure to include a free body diagram as part of your solution.

Now the only information given is a mass=20.4 kg and the angle 22 degrees.

If anyone could help me with this question, it would be greatly appreciated! THANK YOU SO MUCH in advance!


This is what I attempted to do to find a solution:
Fgravity= mg=20.4*9.8=200N

Then to find the tension I did the following:
Tcos(90-22degrees)-200N=0
0.375*T=200N
T=534N------> this would be our vertical component

Resolving horizontally gives:
x-Tcos(22)=0
x=534N*0.927
x=495N
 
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welcome to pf!

hi dani123! welcome to pf! :wink:

(i assume the support bar is horizontal)

yes that's fine :smile:

is anything worrying you about that?​
 
Not anymore! haha I just wasn't feeling very confident with my answer! Thank you very much!
 

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