Help finding the magnitude of this number.

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To find the magnitude of the expression 1/(1 + jwRC), the correct approach involves using the properties of complex numbers. The modulus of a complex number is calculated as |x + jy| = sqrt(x^2 + y^2). The method to find the reciprocal of a complex number typically involves multiplying by its conjugate, simplifying to a rectangular form for easier magnitude calculation. The original poster's method led to an incorrect result due to retaining the imaginary unit j, indicating a misunderstanding of modulus properties. The accurate final result for the magnitude is 1/sqrt(1 + (wRC)^2).
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Hello, I am trying to find out how my teacher got the magnitude of this expression. This is the original expression:
1/(1 + jwRC) j is an imaginary number

Then, he ends up with 1/(sqrt(1 + (wRC)^2)).

I get something nasty like:
sqrt(2/(1 + 2jwRC - wRC))

Thanks.
 
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How did you come to your answer?
 
I squared the original expression and multiplied it by 2, then took the square root of it.
 
Why did you multiply by 2? Anyway, the first indication that something has gone wrong is that you still have the imaginary unit j in your answer -- the modulus should be real.

For any complex number, its modulus can be calculated from:

<br /> \left| {x + jy} \right| = \sqrt {x^2 + y^2 } <br />
 
You could also make use of some of the properties of the modulus listed on this page:

http://planetmath.org/encyclopedia/ModulusOfComplexNumber.html
 
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The usual technique to find the reciprocal of a complex number is to multiply by 1 in the form of the conjugate over itself. That gives you a complex number in rectangular form, making it easier to find the magnitude.

For example, let z = 1/(1 + 2i) (my i is your j)
\frac{1}{1 + 2i} = \frac{1}{1 + 2i} \cdot \frac{1 - 2i}{1 - 2i}
=\frac{1 - 2i}{1 - 4i^2} = \frac{1}{5}(1 - 2i)

Now we can find |z|, which is (1/5)sqrt(1 + 4) = sqrt(5)/5
 
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