Help finishing a linear differential equation. Mechanics

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Homework Statement


Find the distance which an object moves in time t if it starts from rest and has an acceleration d^2x/dt^2 = ge^-kt.
Show that for small t the result is approx "x=(gt^2)/2" and show that for very large t, the speed is approximately constant. the constant is called the terminal speed.

Homework Equations

The Attempt at a Solution


I ended up with v = -(ge^-kt)/k + v_0 and x = (ge^-kt)/k^2 + v_0t + x_0 however I am not sure what to do next. I have tried to solve for k and also set t as zero to get x = g/k^2 but it doesn't seem to be the answer the book is looking for.

Thanks
 
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For small t, look at the Taylor expansion for the exponential.
For large t, take the difference between ##\int_0^{T+\Delta} ge^{-kt}\, dt-\int_0^T ge^{-kt}\, dt ## for large T, or instead of ##T+\Delta,## use ##\infty##.
 
##k## is a given parameter. You don't want to solve for it.

You might find it helpful to use definite integrals, e.g.,
$$\int_{v_0}^v \,dv = \int_0^t ge^{-kt}\,dt.$$ The problem statement says the object starts from rest, so use that bit of information too.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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