HELP having trouble finding calories

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To calculate the calories burned while climbing a rope, one must determine the gravitational potential energy gained, which is calculated using the mass of the person, the height climbed, and the force of gravity. The formula for potential energy is PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height. After calculating the potential energy in Joules, it can be converted to calories using the conversion factor of 1 Joule = 0.239 Calories. Understanding the relationship between mass, height, and gravitational force is crucial for solving such problems. This approach effectively simplifies the calculation of energy expenditure during physical activities.
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HELP! having trouble finding calories

ok, this is probably the easiest thing in the world, but i guess i wasn't paying attention that day in class...ok, i have the mass, and then length a person climbed up a rope, and it wants me to find the number of food calories used to climb 10m up the rope...i have no idea..so ANY help would be appreciated...this is all the info i have m=50kg and L=10m...
 
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Calories is a measure of work or energy. What is the work needed to lift a person up 10 meters? That is, what is his change in gravitational potential? Your answer will be in Joules, but 1 Joule = 0.239 Calories.
 
well thank you for replying so quickly, but is there like an equation or something i can use to find the calories?
 
mezarashi already hinted to you - "gravitational potential"
Find the potential energy gained. This is directly proportional to the mass, distance vertically traveled (height), and force of gravity. Then once you have your answer. Convert it to calories.

KatParker35, when you analyze a problem like this. You must think to yourself - they are telling me vertical distance travelled, then mass of the person. Why are they giving these hints? All you need to do is apply a little thought and then fill in the little gaps.
 
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thank you very much! once you said PE it clicked that i had m,g, and h...thanks again!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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