Help: If A[itex]\subseteq[/itex]B proof C-B[itex]\subseteq[/itex]C-A

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The discussion revolves around proving that if A is a subset of B, then the difference C - B is a subset of C - A. The initial approach involved element-wise proof and the use of logical rules but led to confusion regarding the existence of elements in the sets. A clearer solution was later proposed, utilizing contraposition and definitions of set complements to establish that if an element is in C - B, it must also be in C - A. The final conclusion confirms that the proof is valid, affirming the relationship between the sets as required. Overall, the discussion highlights the importance of logical reasoning and definitions in set theory proofs.
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Homework Statement


Hello, I'm having problems with the following exercise from my homework.

Proof that when A\subseteqB, then it happens that C-B\subseteqC-A


Homework Equations





The Attempt at a Solution


This is how I have been trying to solve it:
1. A\subseteqB // Hyp
2. x\inA\rightarrowx\inB //Element wise proof [1]
3. x\inA \wedge x\inB // which rule allow me to do this? [2]
4. ( x\inA \wedge x\inB) \vee x\inC // Addition [3]
5. (x\inA\veex\inC)\wedge(x\inB\veex\inC) // Distrivutive law [4]
6. x\inA\veex\inC // \wedge OUT [5]
7. x\inB\veex\inC // \wedge OUT [5]
8. y\inC // Hyp (This step is the very confusing one. I'm assuming it exists an element of one set I have no information it actually exists)
9. y\notinB // Modus Ponendo Tollens [7,8]
10. y\inC\wedgey\notinB // \wedge IN [8,9]
11. y\notinA // Modus Ponendo Tollens [6,8]
12. y\inC\wedgey\notinA // \wedge IN [8,11]
13. y\inC\wedgey\notinB \rightarrow y\inC\wedgey\notinA // CP [10, 12]
14. C-B \subseteq C-A // Defs of Difference [13] & Element wise proof

Sorry for my poor english. Thanks in advance for your help.
 
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ozarga said:

Homework Statement


Hello, I'm having problems with the following exercise from my homework.

Proof that when A\subseteqB, then it happens that C-B\subseteqC-A

Homework Equations



The Attempt at a Solution


This is how I have been trying to solve it:
1. A\subseteqB // Hyp
2. x\inA\rightarrowx\inB //Element wise proof [1]
3. x\inA \wedge x\inB // which rule allow me to do this? [2]
4. ( x\inA \wedge x\inB) \vee x\inC // Addition [3]
5. (x\inA\veex\inC)\wedge(x\inB\veex\inC) // Distrivutive law [4]
6. x\inA\veex\inC // \wedge OUT [5]
7. x\inB\veex\inC // \wedge OUT [5]
8. y\inC // Hyp (This step is the very confusing one. I'm assuming it exists an element of one set I have no information it actually exists)
9. y\notinB // Modus Ponendo Tollens [7,8]
10. y\inC\wedgey\notinB // \wedge IN [8,9]
11. y\notinA // Modus Ponendo Tollens [6,8]
12. y\inC\wedgey\notinA // \wedge IN [8,11]
13. y\inC\wedgey\notinB \rightarrow y\inC\wedgey\notinA // CP [10, 12]
14. C-B \subseteq C-A // Defs of Difference [13] & Element wise proof

Sorry for my poor english. Thanks in advance for your help.
Generally, to prove that C-B\subseteq C-A\,, you take an element of set C-B and show that it is an element of set C-A .
 
Thank you SammyS.

I think I figured out:

1. A\subseteqB // hyp
2. x\inA \rightarrow x\inB // for element proof
3. x\notinB \rightarrow x\notinA // Contraposition
4. x\inBc\rightarrowx\inAc // Definition of Set Complement in 3
5. x\inC-B\rightarrowx\inC-A // Definition of Complement in 4
6. C-B\subseteqC-A

Is it right?
 
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