Help Needed: Calculating Coal Delivery Rate with 60kW Motor

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    Coal Motor Rate
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To calculate the coal delivery rate using a 60kW motor, only 90% of the power is effective for work. The formula involves potential energy, where the work done (W) is equal to mass (m) times gravitational acceleration (g) times height (h). By rearranging the power equation, the mass can be determined using m = (Pt)/(gh), factoring in the motor's efficiency. This approach allows for calculating how many kilograms of coal can be delivered per minute. Understanding these calculations is essential for solving the homework question effectively.
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Hey everyone, just wondering if anyone can help me out with a homework question I'm having trouble with. I've been stuck on it for about 45 minutes now, any help will be appreciated. Thanks.

"A conveyor belt is driven by a motor rated at 60kW. Only 90% of the rated power is available for useful work. The coal is to be raised and deposited into a hopper 19.5m above. How many kilograms of coal can be delivered by this motor per minute?"

- Matt
 
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If you use t = 60s, then find the mass through work/potential energy considerations.

P = \frac {W}{t}

W = mgh

P = \frac {mgh}{t}

m = \frac {Pt}{gh}
 
Dont forget to forget to multiply the power by the motor's efficiency!
 

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