Optimize Derivative of Trig Functions Grade 11 Math

In summary, optimizing the derivative of trigonometric functions involves finding the maximum or minimum values of the derivative by setting it equal to zero and solving for the critical points. This process can be applied to various trigonometric functions, such as sine, cosine, and tangent, and is important in understanding the behavior of these functions in calculus. Additionally, the chain rule can be used to find the derivative of more complex trigonometric expressions. This concept is commonly taught in Grade 11 math and is crucial for further understanding of calculus and its applications.
  • #1
livelaughlove
6
0

Homework Statement


there's a picture of the question... from my textbook
http://photos-h.ak.fbcdn.net/hphotos..._1385551_n.jpg
thers a diagram image of the problem too to help understand

Homework Equations



well its a word problem,
i used cosine rule at beginining and then pythagoras...i don't know what to do next but i think you calculare the area and then derivative. but i don't know how (whats the equation for the area)

The Attempt at a Solution


well i used the cosine rule for triangle BCO
BC^2 = 10^2 + 10^2 - 2x10x10 cosθ
BC = √(200-200cosθ)
XY = BC


BY^2 = BX^2 + XY^2 =
400 = BX^2 + (200-200cosθ)
BX^2 = 200 + 200cosθ
BX = √(200+200cosθ)

now what do i do?


reply asap ! :P thankss !
 
Last edited by a moderator:
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  • #2


livelaughlove said:

Homework Statement


there's a picture of the question... from my textbook
http://photos-h.ak.fbcdn.net/hphotos..._1385551_n.jpg
thers a diagram image of the problem too to help understand

Homework Equations



well its a word problem,
i used cosine rule at beginining and then pythagoras...i don't know what to do next but i think you calculare the area and then derivative. but i don't know how (whats the equation for the area)

The Attempt at a Solution


well i used the cosine rule for triangle BCO
BC^2 = 10^2 + 10^2 - 2x10x10 cosθ
BC = √(200-200cosθ)
XY = BC


BY^2 = BX^2 + XY^2 =
400 = BX^2 + (200-200cosθ)
BX^2 = 200 + 200cosθ
BX = √(200+200cosθ)

now what do i do?


reply asap ! :P thankss !

I can't get access to that web site... so you better go with another uploading site like tinypic.com or somewhere else!

AB
 
Last edited by a moderator:
  • #3


oh sorry ! here you go
i hope this way works

http://es.tinypic.com/r/2exa4yb/6

and here's the old link again, fixed it

http://photos-h.ak.fbcdn.net/hphotos-ak-snc3/hs145.snc3/17245_418921415214_614755214_10740817_1385551_n.jpg
 
Last edited by a moderator:
  • #4


livelaughlove said:
oh sorry ! here you go
i hope this way works

http://es.tinypic.com/r/2exa4yb/6

and here's the old link again, fixed it

http://photos-h.ak.fbcdn.net/hphotos-ak-snc3/hs145.snc3/17245_418921415214_614755214_10740817_1385551_n.jpg

I've given all hints needed for the complete answer in the following picture:

http://www.freeimagehosting.net/uploads/th.3b37fcda70.jpg

As for the second question, the only hint is that take the first derivative of the area with respect to theta and then equate the resulting equation with zero. The theta from the new equation with an accuracy of 1/10 of a degree will be your desirable answer.

AB
 
Last edited by a moderator:

1. What is the derivative of a trigonometric function?

The derivative of a trigonometric function is the rate of change of the function at a specific point. It represents the slope of the tangent line to the function at that point.

2. How do you find the derivative of a trigonometric function?

To find the derivative of a trigonometric function, you can use the standard formulas for derivatives of trigonometric functions (such as sin(x), cos(x), tan(x), etc.) or you can use the chain rule if the trigonometric function is nested within another function.

3. Why is it important to optimize derivatives of trigonometric functions?

Optimizing derivatives of trigonometric functions is important because it allows us to find the maximum or minimum values of a function, which is useful in many real-world applications, such as finding the maximum profit or minimum cost in business problems.

4. What are some common mistakes when finding the derivative of a trigonometric function?

Some common mistakes when finding the derivative of a trigonometric function include forgetting to use the chain rule, forgetting to simplify the expression, and making calculation errors with the trigonometric identities.

5. How does finding the derivative of a trigonometric function relate to the unit circle?

The unit circle is a helpful tool in understanding the relationship between trigonometric functions and their derivatives. The coordinates of a point on the unit circle correspond to the values of the trigonometric functions at that point, and the slope of the tangent line to the unit circle at that point is equal to the derivative of the trigonometric function.

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