# Help Tt

1. Nov 3, 2007

### rhxoehwhfh

Dan starts from rest and started running for a distance of 6.0 x 10(power of 1) m in 8 s. [4 Marks]

a) What was Dan’s final velocity at this time?
6*10 = 60 -> 60/8 = 7.5
7.5m/s <-- is this right?

b) What was the acceleration of Dan?

7.5-0 divided by 8 = 0.9375
so 0.9375m/s squared

is question a and b right?.... Can anyone please help me...

2. Nov 3, 2007

### rhxoehwhfh

Can anyone help me with this too please? thanks T.T

3. Nov 3, 2007

anyone...

4. Nov 3, 2007

### rhxoehwhfh

11. a) 60m in 8 sec -> 7.5 m/s
b)d=60m t= 8 v(I)= 0

60m= 32a -> a= 60/32

acceleration -> 1.875 m/s squared

is it right?????

5. Nov 3, 2007

### saket

(b) seems fine.. (assuming constant acceleration)
why dont you try for (a) in a similar fashion!

6. Nov 3, 2007

### Antineutron

I think you had it right the first time for part b, part a looks fine. What is acceleration? Change in velocity over change in time right?

7. Nov 4, 2007

### rhxoehwhfh

thankyou everybody

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