Help: Volume Fluxes and Associated Velocities

geojon
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Suppose that volume transport of an ocean current is 50 x 10^6 m^3/s. Assume that this volume transport is carried in a current of uniform speed which is 50 km wide and 1 km thick. What is the average velocity of the current?

Suppose that the velocity of a current is 0.2 m/s. Assume that the width and thickness of the current are 50 km and 0.5 km respectively. What is the volume transport associated with this current, in m^3/s?
 
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The issue is that I am having a difficult time getting started. I know that velocity is the derivative of speed (or a position with relation to time). I also know that volume transport refers to a mass of water (or water parcel) moving through an area per unit time. What I cannot resolve, is how to relate these variables in order to come up with a formula. The question comes from my graduate level physical oceanography course; I am a transplant to the department (geologist by training). Any help at all would be greatly appreciated? Is my grasp on these terms correct?
 
Follow the homework layout and post in the correct forum.

Forget about mass, your question is only about volume.

This is the only equation you need:

Q = vA
(volumetric flow rate = velocity * area)
 
Thank you for your help. I will try moving forward with this equation.
 
Rearranging the equation Q = v*A to solve for velocity yields the following equation: v = Q/A

Plugging in the numbers we get: v = (50 x 10^6 m^3 s^-1) / (50,000,000 m^2) ...I have converted km to meters at this point

The answer then, is 1 meter/second.

I am not sure of this answer, as this is a graduate level course. The math is not wrong, though; is my approach?
 
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