Help with 3 objects/masses connected by string over frictionless pulley?

AI Thread Summary
The discussion revolves around solving a physics problem involving three masses connected by strings over a frictionless pulley. The user attempts to calculate the downward acceleration of mass M2 using free body diagrams and Newton's second law but struggles with the correct application of the formulas. After several incorrect attempts, including using different masses and equations, the user finds a solution using the formula A = [(M1-M2)/(M1+M2)] * g, arriving at an acceleration of 1.413 m/s². The user also requests assistance with a diagram to clarify the setup but ultimately resolves the issue independently. The thread highlights the importance of correctly applying physics principles in problem-solving.
miamirulz29
Messages
62
Reaction score
0

Homework Statement


Three masses connected by light strings are shown in the figure below (I will try my best in describing the figure):
There is light, frictionless pulley with two masses, M2 and M3, on the left and one mass, M1, on the right. They are all connected by light strings. Given m1 = 10 kg, m2 = 7.48 kg, m3 = 8.01 kg, and g = 9.8 m/s2. The acceleration of gravity is 9.8 m/s2 . Find the downward acceleration of m2 mass. answer in units of m/s^2


Homework Equations


SigmaF= ma
mg=fg

The Attempt at a Solution



I drew three separate free body diagrams for each of the masses.
For M1:
Ft-MG=MA
Ft-98=10a

For M2:
MG-Ft=MA
7.48(9.8)-Ft=7.48a
73.304-Ft=7.48a

So I combined the two equations and got -1.413 m/s^2. I though because it is downward, I didn't need the negative, so I put in UT, 1.413, it was wrong, I also put -1.413, it was also wrong. Then I tried using M3 and combined the acceleration of M3 and M2, which was 8.387, which is also wrong. Then I read on another thread that you can use the equation:
A= [(M1-M2)/(M1+M2)] * G. I got 1.413. I honestly don't know what to do at this point, can somebody please help me. Thanks in advance.
 
Physics news on Phys.org
Anybody? Please?
 
miamirulz29 said:
Anybody? Please?

If you could post the diagram that would help a lot so we would know where to start...
 
Diagram posted. It is on the last page, number 018 (part 1of 3).
 

Attachments

Please can anybody help? I even posted the diagram.
 
Nevermind, figured it out.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top